[FIXED] Why extra var2 byte array is used in hashCode method of StringLatin1 utility class?

Issue

Current code is:

public static int hashCode(byte[] value) {
    int h = 0;
    byte[] var2 = value;
    int var3 = value.length;

    for(int var4 = 0; var4 < var3; ++var4) {
        byte v = var2[var4];
        h = 31 * h + (v & 255);
    }

    return h;
}

Possible code is:

public static int hashCode(byte[] value) {
    int h = 0;
    int var2 = value.length;

    for(int var3 = 0; var3 < var2; ++var3) {
        byte v = value[var3];
        h = 31 * h + (v & 255);
    }

    return h;
}

In java.lang package, there is a utility class called StringLatin1. This class has hashCode method which will be called from String class's hashCode method, if current string value is latin.

PS: I use Java 11.

Solution

Whatever current code you have posted is not the real code; it's the decompiled code which may vary from decompiler to decompiler and therefore you can not rely on it.

Answered By - Arvind Kumar Avinash
Answer Checked By - Timothy Miller (JavaFixing Admin)