Issue
Everything is working fine else why RequestDispatcher showing source code of page?
public class LoginServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {
String uName=req.getParameter("uEmail");
String uPass=req.getParameter("uPass");
try{
DBConnection con=new DBConnection();
if(con.login(uName, uPass)){
HttpSession on = req.getSession();
on.setAttribute("u_id", uName);
res.sendRedirect("dashboard.jsp");
}
else{
RequestDispatcher dis= getServletContext().getRequestDispatcher("/login.jsp");
PrintWriter write = res.getWriter();
write.println("Wrong Username or Passowrd");
dis.include(req, res);
}
}catch(ClassNotFoundException | SQLException e){}
}
}
Page redirecting fine to given url /login.jsp and also showing the error message, but why as source code?
Wrong Username or Passowrd
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
</head>
<body>
<form action="LoginServlet" method="POST" />
<input type="text" name="uEmail" />
<br /><br />
<input type="text" name="uPass" />
<br /><br />
<input type="Submit" name="Register" value="Register" />
<br /><br />
</form>
</body>
</html>
direct link to login.jsp works fine.
Solution
from http://docs.oracle.com/javaee/6/api/javax/servlet/RequestDispatcher.html#include(javax.servlet.ServletRequest, javax.servlet.ServletResponse)
The include method of Request Dispatcher gets the content of the resource that why you are getting the source code in browser.
I think what you want to do is forward the request to login.jsp so use forward method of request dispatcher.
As @JBNizet mentioned in his comment due to your message from Servlet, HTML is going to be invalid.
Answered By - Neenad
Answer Checked By - Timothy Miller (JavaFixing Admin)
