[FIXED] Spring Boot - get current configuration file path in runtime

Issue

I need to get absolute path to current active configuration file in Spring boot that don't locate in classpath or resources

It can be located in default place - project folder, subfolder "config", set via spring.config.location and in random place, also in another disk

Something like "E:\projects\configs\myProject\application.yml"

Solution

Someday I found same question here, but cant find it now

So here my solution, maybe someone needs it

    @Autowired
    private ConfigurableEnvironment env;
    private static final String YAML_NAME = "application.yml";

    private String getYamlPath() throws UnsupportedEncodingException {
        String projectPath = System.getProperty("user.dir");
        String decodedPath = URLDecoder.decode(projectPath, "UTF-8");

        //Get all properies
        MutablePropertySources propertySources = env.getPropertySources();

        String result = null;
        for (PropertySource<?> source : propertySources) {
            String sourceName = source.getName();
            
            //If configuration loaded we can find properties in environment with name like
            //"Config resource '...[absolute or relative path]' via ... 'path'"
            //If path not in classpath -> take path in brackets [] and build absolute path

            if (sourceName.contains("Config resource 'file") && !sourceName.contains("classpath")) {
                String filePath = sourceName.substring(sourceName.indexOf("[") + 1, sourceName.indexOf("]"));
                if (Paths.get(filePath).isAbsolute()) {
                    result = filePath;
                } else {
                    result = decodedPath + File.separator + filePath;
                }
                break;
            }
        }

        //If configuration not loaded - return default path
        return result == null ? decodedPath + File.separator + YAML_NAME : result;
    }

Not the best solution I suppose but it works

If you have any idea how to improve it I would be really appreciate it

Answered By - EoinKanro
Answer Checked By - Katrina (JavaFixing Volunteer)