[FIXED] How to get deploy root directory in servlet based project?

Issue

I am trying to get deploy root directory of my servlet based project from java. I am using the following lines of codes to get the path details.

Type 1:

File directory = new File (".");
try {
    System.out.println ("Current directory's canonical path: " 
            + directory.getCanonicalPath()); 
    System.out.println ("Current directory's absolute  path: " 
                + directory.getAbsolutePath());
}catch(Exception e) {
    System.out.println("Exceptione is ="+e.getMessage());
}

Type 2:

String currentDir = System.getProperty("user.dir");
System.out.println("Current dir using System:" +currentDir);

While executing the above codes from main class i am getting user directory. When i executes from server side, gets as, "Current dir using System:D:\Apache Tomcat 6.0.16\bin". But my project is located in D:\Apache Tomcat 6.0.16\wepapps\SampleStructs.

Please give me any suggestions for this and help me out of this.

Solution

It because when you execute from main class everything is fine, but this code runs on server it looks into current directory and current the directory structure is Apache 'bin' from where you have started the server(run.bat).

Answered By - Vallabh Patade
Answer Checked By - Willingham (JavaFixing Volunteer)