Issue
Below is the code snippet; basically, I am trying to propagate the exception when the error code is anything other than 200.
ResponseEntity<Object> response = restTemplate.exchange(url.toString().replace("{version}", version),
HttpMethod.POST, entity, Object.class);
if(response.getStatusCode().value()!= 200){
logger.debug("Encountered Error while Calling API");
throw new ApplicationException();
}
However in the case of a 500 response from the server I am getting the exception
org.springframework.web.client.HttpServerErrorException: 500 Internal Server Error
at org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:94) ~[spring-web-4.2.3.RELEASE.jar:4.2.3.RELEASE]
Do I really need to wrap the rest template exchange method in try? What would then be the purpose of codes?
Solution
You want to create a class that implements ResponseErrorHandler
and then use an instance of it to set the error handling of your rest template:
public class MyErrorHandler implements ResponseErrorHandler {
@Override
public void handleError(ClientHttpResponse response) throws IOException {
// your error handling here
}
@Override
public boolean hasError(ClientHttpResponse response) throws IOException {
...
}
}
[...]
public static void main(String args[]) {
RestTemplate restTemplate = new RestTemplate();
restTemplate.setErrorHandler(new MyErrorHandler());
}
Also, Spring has the class DefaultResponseErrorHandler
, which you can extend instead of implementing the interface, in case you only want to override the handleError
method.
public class MyErrorHandler extends DefaultResponseErrorHandler {
@Override
public void handleError(ClientHttpResponse response) throws IOException {
// your error handling here
}
}
Take a look at its source code to have an idea of how Spring handles HTTP errors.
Answered By - carcaret
Answer Checked By - Pedro (JavaFixing Volunteer)