[FIXED] How to send json file with 2 different values?

Issue

I send JSON file (now from postman) the body is like this:

{
    "email": "[email protected]",
    "password": "123456"
}

the method on the controller is:

public Company getCompanyDetailsByEmailAndPassword(String email, String password) {
        System.out.println("this is email: " +email); // added the sysout to understand what arrived.
        System.out.println("this is password: " +password);
        return companyRepository.findByEmailAndPassword(email, password);
    }

I get an error -

this is email: {
    "email": "[email protected]",
    "password": "123456"
}

this is password: null
2022-04-04 18:14:07.830 DEBUG 6076 --- [nio-8080-exec-8] org.hibernate.SQL                        : select company0_.id as id1_0_, company0_.email as email2_0_, company0_.name as name3_0_, company0_.password as password4_0_ from companies company0_ where company0_.email=? and (company0_.password is null)
Hibernate: select company0_.id as id1_0_, company0_.email as email2_0_, company0_.name as name3_0_, company0_.password as password4_0_ from companies company0_ where company0_.email=? and (company0_.password is null)
2022-04-04 18:14:07.831 TRACE 6076 --- [nio-8080-exec-8] o.h.type.descriptor.sql.BasicBinder      : binding parameter [1] as [VARCHAR] - [{

how to resolve that?

Solution

Simplest way is to write a simple class

public class EmailIdHolder {
  public String email;
  public String password;
  // add setters and getters here
} 

Change your controller method to:

public Company getCompanyDetailsByEmailAndPassword(EmailIdHolder id) {
        System.out.println("this is email: " +id.getEmail); // added the sysout to understand what arrived.
        System.out.println("this is password: " +id.getPassword);
        return companyRepository.findByEmailAndPassword(email, password);
    }

Answered By - Michael Gantman
Answer Checked By - Clifford M. (JavaFixing Volunteer)